X^2+12x=245

Solution for X^2+12x=245 equation:

X^2+12X=245

We move all terms to the left:

X^2+12X-(245)=0

a = 1; b = 12; c = -245;
Δ = b2-4ac
Δ = 122-4·1·(-245)
Δ = 1124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1124}=\sqrt{4*281}=\sqrt{4}*\sqrt{281}=2\sqrt{281}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{281}}{2*1}=\frac{-12-2\sqrt{281}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{281}}{2*1}=\frac{-12+2\sqrt{281}}{2}
$